two distinct lines cannot have more than one point in common
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Two distinct lines cannot have more than one point in common. Thus, onlyone line passes through two distinct points P & Q. But here we assumedboth in 1 and 2 .
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u didn't mension in the question
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Yes it
Given:AB and Cd are line segment
To prove,One point in common
Proof,: AB intersect two distinct points say P and Q ,Hence it contains P and Q.similarly CD passes and contains P and Q ,But according to axiom ,One line can pass Throught two different points
So our assumption clashes with the axiom that two distict lines can have more than one point is wrong ,
Hence,two distinct lines cannot have more than one point in common
Cheers
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Given:AB and Cd are line segment
To prove,One point in common
Proof,: AB intersect two distinct points say P and Q ,Hence it contains P and Q.similarly CD passes and contains P and Q ,But according to axiom ,One line can pass Throught two different points
So our assumption clashes with the axiom that two distict lines can have more than one point is wrong ,
Hence,two distinct lines cannot have more than one point in common
Cheers
Follow me friend ###
lines plz
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