Physics, asked by hihello123, 6 months ago

Two drops of water which are falling in air are having mass ratio 1 : 27, what will be ratio of their

terminal speed​

Answers

Answered by sakshisolanki9265
3

Answer:

27:8

Explanation:

pls mark me as brilliant

Answered by rinayjainsl
0

Answer:

The ratio of Terminal velocities is 1:27

Explanation:

Given that,

The ratio of mass of drops of water is 1:27.

The terminal velocity of a droplet in terms of mass is given as

V _{t} =  \frac{Mg}{6\pi \: nr}

Where

M=Mass of the droplet

g=Acceleration due to gravity

n=Coefficient of viscosity

r=Radius of the droplet

In the RHS of above expression except mass all terms are constant.Therefore

V _{t} ∝M \\  \frac{(V _{t} ) _{1} }{(V _{t}) _{2} }  =  \frac{M _{1} }{M _{2}}

Substituting the known ratio,we get

\frac{(V _{t} ) _{1} }{(V _{t}) _{2} }  = \frac{1}{27}

Therefore,the ratio of Terminal velocities is 1:27

#SPJ3

Similar questions