Question

Two duce are thrown.

(i)The sum of the numbers on the upper faces is at the most 3.
(ii) Sum of the digits on the upper face is more than 20.​

Answer 1

Answer:

S={(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)}

n(s)=36

Let A be the event when the sum of the digits in the upper face is at most 3

A={(1,2) (2,1)}

n(A)= 2

p(A)=2/36 =1/18

Let B be the event where sum of the digits in the upper face is more than 20

B={}

n(B)=0

p(B) = 0/36 =0