Two eaual sides of a triangle are 5m less thrice the third side. if the perimeter of the triangle is 53m then length of each equal side is
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1
let the third side be x
first side and second side =3x-5
perimeter of triangle =sum of all sides
53=x+3x-5+3x-5
53=7x-10
7x=53+10
7x=63
x=63÷7
x=9
first side =3x-5=3×9-5=27-5=22
therefore second side =22
third side =x=9
first side and second side =3x-5
perimeter of triangle =sum of all sides
53=x+3x-5+3x-5
53=7x-10
7x=53+10
7x=63
x=63÷7
x=9
first side =3x-5=3×9-5=27-5=22
therefore second side =22
third side =x=9
DibyaSampad:
given that equal sides are 5 less than thrice of third side
Answered by
2
let the length of third side be x
then other two becomes 3x-5
Given perimeter of the triangle=53
So the length of each equal sides =3x-5=(3x9)-5=22
then other two becomes 3x-5
Given perimeter of the triangle=53
So the length of each equal sides =3x-5=(3x9)-5=22
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