Question

Two elastic bodies P and Q having equal masses are moving along the same line with velocities of 16 m/s and 10m/s respectively. Their velocities after the elastic collision will be in m/s -

Answer 1

in an elastic collision, we can apply conservation of linear momentum and conservation of energy theorem.

so, first of all, we apply law of conservation of linear momentum .
Let velocities after collision of P and Q are $v_1$ and $v_2$ respectively.

so, $m\times16+m\times10=m(v_1+v_2)$

$26=v_1+v_2$..........(1)

now apply law of conservation of energy theorem,

$\frac{1}{2}m16^2+\frac{1}{2}m10^2=\frac{1}{2}mv_1^2+\frac{1}{2}mv_2^2$

$356=v_1^2+v_2^2$.......(2)

from equation (1) and (2),
$v_1=10m/s$ and $v_2=16m/s$

means, in perfectly elastic collision, bodies exchange their velocities.
that's why velocity of P is 10m/s and velocity of Q is 16m/s

Answer 2

Heya mate,

Answer:

When two bodies of equal masses collide elastically with each other, they interchange their velocities.

So v1 = 10m/s and V2=16m/s

Hope it works (. ❛ ᴗ ❛.)