Question

Two electons are placed at the same distance in air. Compare the gravitational force and electrostatic force between them

Answer 1

Answer:

Given:

The mass of an electron, m = 9.1 × 10⁻³¹ kg

The charge on an electron, q = 1.6 × 10⁻¹⁹ C

To Find:

To compare the gravitational force and the electrostatic force between the two electrons.

Calculation:

- Let the distance between the two electrons be R

- The gravitational force of attraction = Gm²/R²

⇒ F (g) = 6.67 × 10⁻¹¹ × (9.1 × 10⁻³¹)²/R²

⇒ F (g) = 55.23 × 10⁻⁷²/R² N ...(i)

- The electrostatic force of attraction = kq²/R²

⇒ F (e) = 9 × 10⁹ × (1.6 × 10⁻¹⁹)²/R²

⇒ F (e) = 23.04 × 10⁻²⁹/R² N ...(ii)

- Now, dividing (ii) by (i), we get:

F(e) / F(g) = (23.04 × 10⁻²⁹/R²)/(55.23 × 10⁻⁷²/R²)

⇒ F(e) / F(g) = 4.17 × 10⁴²

⇒ F(e) = 4.17 × 10⁴² F(g)

- So, in the given case the electrostatic force is 4.17 × 10⁴² times stronger than the gravitaional force of attraction.