Question

Two electric bulbs have resistances
in the ratio 1:2. If they are joined in
series, the energy consumed in these
are in the ratio
.(1:2, 2:1,
4:1, 1:1)​

Answer 1

Hey mate

Let the voltage be V across both the bulbs.And resistance of first bulb is R; hence resistance of second bulb is 2R.

So if we find the ratio of powers we have

V^2/R : V^2/2R

= 1 : 1/2

= 2 : 1

hence , (i) is correct...