Physics, asked by mail2ranvir05, 10 months ago

Two electric bulbs have resistances in the ratio 1:2. If they are joined in series, the energy consumed in them is in the ratio:
(a) 2:1
(b) 1:2
c) 4:1
(d) 1:1

Answers

Answered by titli12381
5

Answer:

(b)

Explanation:

Let the voltage be V across both the bulbs.And resistance of first bulb is R; hence resistance of second bulb is 2R.

So if we find the ratio of powers we have

V^2/R : V^2/2R

= 1 : 1/2

= 2 : 1

the correct option is option( ii)

Hope it helps to you.

Answered by sahatrupti21
4

Answer:

(b)

Explanation:

Let the voltage be V across both the bulbs.And resistance of first bulb is R; hence resistance of second bulb is 2R.

So if we find the ratio of powers we have

V^2/R : V^2/2R

= 1 : 1/2

= 2 : 1

the correct option is option( ii)

Hope it helps to you.

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