Two electric bulbs have resistances in the ratio 1:2. If they are joined in series, the energy consumed in them is in the ratio:
(a) 2:1
(b) 1:2
c) 4:1
(d) 1:1
Answers
Answered by
5
Answer:
(b)
Explanation:
Let the voltage be V across both the bulbs.And resistance of first bulb is R; hence resistance of second bulb is 2R.
So if we find the ratio of powers we have
V^2/R : V^2/2R
= 1 : 1/2
= 2 : 1
the correct option is option( ii)
Hope it helps to you.
Answered by
4
Answer:
(b)
Explanation:
Let the voltage be V across both the bulbs.And resistance of first bulb is R; hence resistance of second bulb is 2R.
So if we find the ratio of powers we have
V^2/R : V^2/2R
= 1 : 1/2
= 2 : 1
the correct option is option( ii)
Hope it helps to you.
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