Two electric bulbs have resistances R and 3R respectively. They are connected in parallel to a power source of voltage V. If the two resistors are to be replaced by a single resistor. What will be the value of this resistor? *
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0.75 R
1.33 R
4 R
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If R and 3R are in parallel then their equivalent resisitance is
= R * 3R /( R + 3R ) = 3/4 R = 0.75 R
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tqsm for ur TNX ♥️ dr
l hope it will help u ☺️☺️☺️
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