Question

Two electric bulbs of 100W and 200V are put in series combination is supplied 100V. The power consumption of each bulb will be? (a)100/2W (b)100/4W (c)100/8W (d)100/16W​

Answer 1

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Answer 2

Answer:

100/16

Step-by-step explanation:

P=v2/R  R= v2/P200*200/100= 400 Ohm

In series

R total =R1+R2 =400+400=800 ohms

Now  P=v2/R =100*100/800

R=100/8 ( for series combination of 2 resistors )

For one resistor power consumption is

P”=P/2 = 100/8/2= 100/16