Question

Two electric bulbs, one of 200 V, 40W and other
of 200 V, 100W are connected in a domestic
circuit. Then
(a) they have equal resistance
(b) the resistance of 40W bulb is more than
100W bulb
(c) the resistance of 100W bulb is more than
40 W bulb
(d) they have equal current through them​

Answer 1

Answer:

1st bulb,

potential difference = 220V

Power = 40 W

therefore, resistance = v²/ p

= 220²/40 Ω

= 1210 Ω

2nd bulb,

potential difference = 220 V

power = 100 W

therefore, resistance = v²/p

= 220²/100 Ω

= 484 Ω

so, a} No

b} Yes

c} No

d} Yes

please mark it as brainlist...