two electric bulbs P and Q have the resistance is in the ratio of 1 ratio 2 they are connected in series across a battery find the ratio of the power dissipation in these bulbs
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ans: 2:1
solution : Since I is constant as resistances are connected in series,
therefore P is inversely proportional to R
hence,
=> P1 : P2 = R1: R2
since R2 : R1 = 1:2
=> P1 : P2 = 1:2
solution : Since I is constant as resistances are connected in series,
therefore P is inversely proportional to R
hence,
=> P1 : P2 = R1: R2
since R2 : R1 = 1:2
=> P1 : P2 = 1:2
Answered by
0
Since in series combination current is same so resistance will be propotional to power dissipated
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