Question

Two electric bulbs p and q have their resistances in the ratioof 1 : 2. They are connected in series across abattery. Find the ratio of the power dissipation in these bulbs

Answer 1

Two electric bulbs P and Q have resistance in the ratio of 1:2, are connected in series. Find the ratio of power dissipation?

As we know p=V*I.

Now coming to series circuit current constant so P=V^2/R. So if R more in series power dissipation is less and low R having high power dissipation . Invers relationship.

Coming to parallel circuit voltage constan so we can write P=IR*I (as V=I*R)

That means P=I^2R.

So it shows if R is more power dissipation is more and low R low will be the power dissipation. In parallel circuit.

So, ratio of power dissipation will be R2/R1= 2/1

Hope I clear you

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