Question

Two electric bulbs whose resistance are in the ratio 1 : 2 are
arranged in parallel to a constant voltage source. The
powers dissipated in them have the ratio
(a) 1 : 2 (b) 1 : 1 (c) 2 : 1 (d) 1 : 4

Answer 1

Answer:

P1:P2 = 2:1(Option c)

Explanation -

In parallel combination, voltage acting on the bulbs will be same. i.e. V.

Power dissipated by 1st bulb is,

P1 = V^2/R1

Power dissipated by 2nd bulb is,

P2 = V^2/R2

Ratio of power dissipated is -

P1/P2 = (V^2/R1) / (V^2/R2)

P1/P2 = R2/R1

Given that R1/R2 = 1/2.

P1/P2 = 1/(1/2)

P1/P2 = 2

Hence, ratio of power dissipation in two bulbs is 2:1.

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Answer 2

Answer:

pls mark as brainlist answer