Question

Two electric bulbs whose resistances are in the ratio 1:2 are connected in parallel to a source of constant voltage. What is the ratio of power dissipation in these bulbs?

Answer 1

Dear Student,

◆ Answer -

P1:P2 = 2:1

● Explanation -

In parallel combination, voltage acting on the bulbs will be same. i.e. V.

Power dissipated by 1st bulb is,

P1 = V^2/R1

Power dissipated by 2nd bulb is,

P2 = V^2/R2

Ratio of power dissipated is -

P1/P2 = (V^2/R1) / (V^2/R2)

P1/P2 = R2/R1

Given that R1/R2 = 1/2.

P1/P2 = 1/(1/2)

P1/P2 = 2

Hence, ratio of power dissipation in two bulbs is 2:1.

Thanks dear. Hope this helps you...

Answer 2

Answer:

P =V^2/R

So,

P1=V^2/R1

P2=V^2/R2

P1/P2=R2/R1

and R2/R1 is given that is 1:2

so,

P1/P2=2/1

The power dissipated will be 2:1

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