Question

two electric charges 3 micro coloumb and 5 micro coloumb are. located 20 cm apart in a medium of dielectric constant 1 and calculate the potential midway between them​

Answer 1

Answer:

Two point charges qA = 3 μC and qB = −3 μC are located 20 cm apart in vacuum. (a) What is the electric field at the midpoint O of the line ...

Answer 2

Given:

Two electric charges 3 micro coloumb and 5 micro coloumb are located 20 cm apart in a medium of dielectric constant 1.

To find:

Electrostatic Potential midway between them.

Calculation:

Let Electrostatic potential at the specified point be "V" and "d" is half of separation distance. k is dielectric constant = 1.

$\therefore \: V = \dfrac{(q1)}{4\pi \epsilon_{0}k d} + \dfrac{(q2)}{4\pi \epsilon_{0}k d}$

$= > \: V = \dfrac{1}{4\pi \epsilon_{0}d} \bigg \{(q1) + (q2) \bigg \}$

$= > \: V = \dfrac{9 \times {10}^{9} }{( \frac{0.2}{2}) } \bigg \{(5 + 3) \times {10}^{ - 6} \bigg \}$

$= > \: V = \dfrac{9 \times {10}^{9} }{0.1 } \bigg \{8 \times {10}^{ - 6} \bigg \}$

$= > \: V = 9 \times {10}^{10} \times \bigg \{8 \times {10}^{ - 6} \bigg \}$

$= > \: V = 72 \times {10}^{4} \: volt$

So, final answer is:

$\boxed{\rm{\: V = 72 \times {10}^{4} \: volt}}$