two electric charges of 9 uc and _3uc are placed 0.16m apat in air .there will be a point p at which electric potential is zero on the line joining the two charges and in between then .the distance of p from 9 uc charge is
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Sahi hai na yaar..... pura aas paas hai...Usi type ks question
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let the point be x in b/w 2 charges
V = KQ/R
so K*9/x = K*3/(.16-x)
so after solving we get x = .12m from 9 microC charge
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