Two electric lamps of 100W and 12W are connected in parallel to a supply voltage of 200V. Calculate total current flowing through the circuit.
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In the First Electric Lamps,
Power = 100 W
Potential = 200 V
[Since. Potential remains same in the Parallel].
∵ Power = (Potential)²/Resistance
∴ Resistance = (Potential)²/Power
∴ Resistance = (200)²/100
= 400 Ω
In the Second Electric lamps,
Power = 12 W.
Potential = 200 V
[Since, the Potential remains same in the Parallel].
∴ Resistance = (200)²/12
= 3333.33 Ω
Now, Equivalent Resistance in the Circuit will be given by the Formula,
1/Req. = 1/R₁ + 1/R₂
= 1/400 + 1/3333.33
= 0.0025 + 0.0003
= 0.0028
∴ Req. = 1/0.0028
= 357.14 Ω
Now, Using the Ohm's law,
V = I × Req.
∴ I = 200/357.14
⇒ I = 0.56 A.
Hence, the total current flowing through the circuit is 0.56 A.
Hope it helps.
Power = 100 W
Potential = 200 V
[Since. Potential remains same in the Parallel].
∵ Power = (Potential)²/Resistance
∴ Resistance = (Potential)²/Power
∴ Resistance = (200)²/100
= 400 Ω
In the Second Electric lamps,
Power = 12 W.
Potential = 200 V
[Since, the Potential remains same in the Parallel].
∴ Resistance = (200)²/12
= 3333.33 Ω
Now, Equivalent Resistance in the Circuit will be given by the Formula,
1/Req. = 1/R₁ + 1/R₂
= 1/400 + 1/3333.33
= 0.0025 + 0.0003
= 0.0028
∴ Req. = 1/0.0028
= 357.14 Ω
Now, Using the Ohm's law,
V = I × Req.
∴ I = 200/357.14
⇒ I = 0.56 A.
Hence, the total current flowing through the circuit is 0.56 A.
Hope it helps.
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