Question

two electric lamps of 40 watt each are connected in parallel the power consumed by the combination will be????

Answer 1

The power consumed by the combination will be 80 W.

Explanation:

The total power consumed in a parallel circuit is equal to the sum of the power consumed by the individual resistors.

So, for two electric lamps the combination of power is given by

$P=P_{1} +P_{2}$

Given $P_{1} =P_{2}=40W$.

Substitute the given values, we get

P = 40 W + 40 W

P = 80 W

Thus, the power consumed by the combination will be 80 W.

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Answer 2

The power consumed by the combination is 80 watt.

Given:

Power = P1 = 40 watt

Power = P2 = 40 watt

To find:

Power of parallel combination = Pt = ?

Solution:

From question, we know that when the circuit is in parallel combination then the power of the circuit is equal to sum of the power of each component.

Pt = P1 + P2

On substituting the given values, we get,

Pt = 40 + 40

Therefore Pt = 80 watt