Two electrical devices of power rating 1kW and 2kW are connected (a) in series and (b) in parallel. The ratio of the power rating of the combination in case of (a) to that in case of (b) is?
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Answered by
3
Power of each bulb = 1000W
Voltage= 250V (as in parallel voltage remains same)
P=
R
V
2
1000=
R
250×250
R=
4
250
Ω
Two resistance in parallel:
So equivalent resistance =
R+R
R+R
Req=
2
R
Req=
8
250
Ω
Rate of heating =
Req
V
2
=
250
250
×8×250=2000W
=2kW
Answered by
2
Answer:
Power of each bulb = 1000W
Voltage= 250V (as in parallel voltage remains same)
P=
R
V
2
1000=
R
250×250
R=
4
250
Ω
Two resistance in parallel:
So equivalent resistance =
R+R
R+R
Req=
2
R
Req=
8
250
Ω
Rate of heating =
Req
V
2
=
250
250
×8×250=2000W
=2kW
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