Question

Two electrodes maintained at a potential difference of 100 V. An electron moving from cathode to anode gains kinetic energy: (A) 160 * 10-" Erg (Westbengal/ NTSE Stage-1/2015) (B) 100 Joule (C) 160 x 10-19 Joule (D) 100 Erg​

Answer 1

Explanation:

KE= q×E

K E = 1.6×10^-19×100= 160×10^-19 Joules

Answer 2

Answer:

C

Explanation:

Given: Potential difference, V= 100 V

Charge, q=1.6x10^-19 C

Kinetic energy is given by,

E=qV

E=1.6x10^-19 X 100 = 1.6x10^-17J

Hence, we get kinetic energy, E=1.6x10^-17J.