Two electrolytic cells are connected in series containing CuS04 solution and molten AICI3. If in electrolysis 0.4 moles of 'Cu' are deposited on cathode of first cell. The number of moles of
'Al' deposited on cathode of the second cell is....
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Answer:
Given,
Moles of Cu=0.4
Number of moles of Al=?
According to Faraday's second law:
moles of Almoles of Cu=chemical equivalent of Alchemicaf eqivalent of Cu -----------(1)
Chemical equivalent=valencyatomic weight
For CuSO4
Cu2++2e−→Cu
and for AlCl3
Al3++3e−→Al
Thus, Chemical equivalent of Cu =21
and Chemical equivalent of Al =31
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Answer:
the current passed will be same as they are in series. Hence we use no. of moles deposited is inversely proportional to no. of electrons transferred
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