Question

Two electrolytic cells, one containing silver
nitrate solution and the other copper sulphate
solution, were connected in series. A steady
current of 2 A was passed through them until
0-003 kg of silver was deposited at the cathode of
the first cell. How long did the current flow ?
What mass of copper was deposited in the second
cell ?​

Answer 1

we have,
Ag
+
+e
−
→Ag

w=
96500
E∗I∗t
​


1.018=
96500
108∗2.5∗t
​


t=363.8sec
for mass of copper deposited,
w=
n∗96500
E∗I∗t
​


w=
2∗96500
63.5∗2.5∗363.8
​


w=0.598g