Question

Two electrons are placed at distance a distance such that electrostatic force between both the electrons is equal to sum of weight of both the electrons calculate value of d

Answer 1

Thus the distance between the electron is 11.25 m

Explanation:

F = [k (q1) × (q2) ] / [ d²]

The value of constant k = 9 × 10^9

q1 & q2 is charge on electron.

q1= q2= q = 1.6× 10^(-19) C

F = electrostatic force = sum of weight of both electron

F = m+m = 2m = 2×[ 9.1× 10^(-31) ]

F= k × q² / d² = 2m

k × q² / 2m = d²

Putting value of k, q and m.

We get

d² = 126.59

Taking square root on both sides.

√d² =  √126.59

d = 11.25 m

Thus the distance between the electrons is 11.25 m