Two electrons are placed one at north pole and other at south pole of earth find the force between them given diameter of the earth=12800 how to solve
Answers
Given: Two electrons are placed one at north pole and other at south pole of earth.
To find: The force between them?
Solution:
- Now we have given that the electrons are placed at north pole south pole of earth, so the distance between them will be equal to the diameter of the earth which is provided as 12800 km .
So, G = 6.67 x 10^-11 ,
r = 12800 km
m1 = m2 = 9.1 x 10^-31
- We know that F = G ( m1 x m2 ) / r^2 , so putting values in this, we get:
F = 6.67 x 10^-11 x ( 9.1 x 10^-31)² / (12800)²
F = 552.34 x 10^-73 / 1.6384 x 10^8
F = 337.121 x 10^-81 kg / (1000 m)² x m³ / s²
F = 337.121 x 10^-89 kg m / s²
Answer:
So the force between two electrons is 337.121 x 10^-89 kg m / s².
Answer:
Now we have given that the electrons are placed at north pole south pole of earth, so the distance between them will be equal to the diameter of the earth which is provided as 12800 km
So, G = 6.67 x 10^-11 r = 12800 km m1 = m2 = 9.1 x 10^-31
We know that F=G ( m1 x m2) /r^2 so putting values in this, we get: F = 6.67 x 10^-11 x (9.1 x 10^-31)²/
(12800)²
10^8
F = 552.34 x 10^-73/1.6384 x
F = 337.121 x 10^-81 kg/(1000 m)²
F = 337.121 x 10^-89 kg m / s²