Question

Two electrons each of mass 9.1*10-31 kg are at a distance of 10a0 .calculate the gravitational force of attraction between them.

Answer 1

F = GMm/d²
= Gm²/d² ………[∵ M = m]
= G (m/d)²
= (6.67 × 10^-11 N m^2/kg^2) × [(9.1 × 10^-31 kg) / (10 × 10^-10 m)]^2
= 5.52 × 10^-53 Newtons

∴ Gravitational Force between them is 5.52 × 10^-53 Newtons

Answer 2

Answer:

5.52×10^-53N

Explanation:

F = $\frac{GMm}{d^{2} }$

= $\frac{Gm^{2} }{d^{2} }$

= G{$\frac{m}{d}$}²

= (6.67 × $10^{-11}$ N$m^{2} kg^{-2}$){ $\frac{9.1 * 10^{-31}}{10*10^{-10\\}}$  }²

= 5.52 × $10^{-53}$ N