Question

two electrons each of mass 9.1*10^-31 kg are kept at a distance 10^-10m . calculate the gravitational force between them​

Answer 1

ANSWER:

• $F = 5.526 \times {10}^{ - 51}N$

GIVEN:

• Mass of electron = $9.1\times10^{-31}\:kg$

• Disatance between them = $10^{-10}\:m$

FORMULA:

$\sf{ \boxed{ \bold{F =\dfrac{Gm_1m_1}{ {r}^{2}}}}} \\ \\ \textsf{Here m_1 = m_2 = m}$

EXPLANATION:

• m = $9.1\times10^{-31}\:kg$

• r = $10^{-10}\:m$

• G = $6.673 \times 10^{-11} Nm^2/kg^2$

$F = \dfrac{6.673 \times {10}^{ - 11} \times {(9.1 \times {10}^{ - 31}})^{2} }{ { ({10}^{ - 10} )}^{2} } \\ \\ \\ F = \dfrac{6.673 \times 82.81 \times {10}^{ - 11} \times {10}^{ - 62} }{ {10}^{ - 20} } \\ \\ \\ F = 552.59 \times {10}^{ - 73} \times {10}^{20} \\ \\ \\ F = 540.5 \times {10}^{ - 53} \\ \\ \\ F = 5.526 \times {10}^{ - 51}$

$Hence \: \: the \: \: force \: \: acting \: will \: \: be \: \: \\ F = 5.526 \times {10}^{ - 51}N$