Question

Two elements A and B belong to the 3rd period of modern periodic table and are in group 2 and 13 respectively. Compare their following characteristics in tabular
form
(i) Number of electrons in their atoms
(ii)Size of their atoms
(iii) Their tendency to lose electrons
(iv) The formula of their oxides
(v) Their metallic character
vi) The formula of their chlorides. (with explanation) ​

Answer 1

Given,

A is in group 2 and period 3

B is in group 13 and period 3

1 - No. of electrons in A = 12 and B = 13 (A<B)

2 - B will have a smaller atomic size than A ( A>B)

3- A will lose more electrons easily (A>B)

4- AO and B2O3

5- A is more metallic than B

6- ACl2 and BCl3 ( because A has 2 valence electrons and B has 3 valence electrons

Answer 2

Explanation:

element A element B

(i) number of 12 13

electrons

(ii) size of their bigger smaller than

atom A

(iii) tendency to more less

lose electrons

(iv) formula of AO B2O3

oxide

(v) metallic more less

character