Question

Two elements A and B have atomic number 12 and 17 respectively.
1) write the electronic configuration of A and A
2) which type of Bond A and B will form?
3) write the formula of the compound formed by A and B

Answer 1

1= 2,8,8
2= single bond and elctrovalent bond
c6 h12 o6
hope it's help you

Answer 2

Answer:

1)Electronic configuration of element A - 2,8,2

Electronic configuration of element B - 2,8,7

2)Ionic bond is formed by the elements A and B

3)The formula of the compound formed by A and B is $AB_2$.

Explanation:

1) Given the atomic number of A is 12

The electronic configuration of A  is 2,8,2

The atomic number of B is 17

The electronic configuration of B is 2,8,7

2) Since the number of electrons in the outermost shell of element A is 2, It has a tendency to loose these two electrons, while element B, which has 7 electrons in its outermost shell tends to receive the electrons.

∴The type of bond formed by the elements A and B are ionic bond.

3) Since the valency of element A is 2, and hence it has a tendency to loose two electrons. The valency of element B is 1, the element B receives one electron. Hence in the compound formed by A and B, one atom of A reacts with two atoms of B.

∴ The formula of the compound formed by A and B is $AB_2$.

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