Question

Two elements X and Y have atomic weight of 14
and 16. They form a series of compounds A,B,C,X,Y:
is present in the ratio 1:2:3:4:5. If the compound AS
has 28 parts by weight of X and 16 parts by weight
of Y, then the compoud C will have 28 parts by
weight of X and
1) 32 parts by weight of Y
2) 48 parts by weight of Y
3) 64 parts by weight of Y
4) 80 parts by weight of Y​

Answer 1

16*3 =48 part of y will be present in it

Answer 2

Answer:

2) 48 parts of Y

Explanation:

Compound A has 28 parts of X + 16 parts of Y.

Compound C has 28 parts of X + ?.

Y(a) : Y(c)= 1:3

Therefore Y(a)/Y(c) = 16×3= 48 parts of Y.