Physics, asked by Tejanshusethi6800, 1 year ago

Two ends of a uniform conductor of length / are attemperature 10°C and 100°C respectively. Thetemperature at point P at distance from the hotend, as shown in the figure, is (assuming heattransfers by conduction only)

Answers

Answered by nirman95
6

Given:

Two ends of a uniform conductor of length are at temperature 10°C and 100°C respectively.

To find:

Temperature at point P :

Calculation:

Let length of conductor be L and temperature at point P be \theta

Let point P be situated at a distance of "x" from hot end .

Since Heat Current doesn't accumulate at a point, we can say :

 \sf{ \therefore \: H1 = H2}

 \sf{ =  >  \:  \dfrac{100 -  \theta}{ \{ \frac{x}{k(area)} \} }  = \dfrac{  \theta - 10}{ \{ \frac{L - x}{k(area)} \} }}

 \sf{ =  >  \:  \dfrac{100 -  \theta}{ \{ \frac{x}{ \cancel{k(area)}} \} }  = \dfrac{  \theta - 10}{ \{ \frac{L - x}{ \cancel{k(area)}} \} }}

 \sf{ =  >  \:  \dfrac{100 -  \theta}{ \{ x \} }  = \dfrac{  \theta - 10}{ \{ L  - x\} }}

 \sf{ =  >  \:   \theta L = 100L - 100x + 10x}

 \sf{ =  >  \:   \theta L = 100L - 90x }

 \sf{ =  >  \:   \theta  =  \dfrac{100L - 90x}{L} }

So , temperature at point P is :

 \boxed{ \red{ \sf{  \:   \theta  =  \dfrac{100L - 90x}{L} }}}

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