Physics, asked by sushank6828, 9 months ago

Two engines A and B have their sources at 400K and 350K and sinks at 350K and 300K respectively. Which is more efficient and by how much?

Answers

Answered by nirman95
7

Answer:

2 engines A and B such that:

For Engine A :

  • Source Temperature = 400K
  • Sink Temperature = 350 K

For Engine B:

  • Source temperature = 350 K
  • Sink Temperature = 300 K

To Find:

Which engine I more efficient and by how much ?

Calculation :

For Engine A :

 \eta = 1 -  \frac{sink \: temp.}{source \: temp.}  \\

 =  >  \eta = 1 -  \frac{350}{400}  \\

 =  >  \eta = 1 -  \frac{7}{8}  \\

 =  >  \eta =  \frac{1}{8}  \\

  =  >  \eta = 0.125

For Engine B:

 \eta = 1 -  \frac{sink \: temp.}{source \: temp.}  \\

 =  >  \eta = 1 -  \frac{300}{350}  \\

 =  >  \eta = 1 -  \frac{6}{7}  \\

 =  >  \eta =  \frac{1}{7}  \\

 =  >  \eta =  0.142

So Engine B is more efficient than

Engine A.

Efficiency of Engine B is more than Engine A by (0.142 - 0.125) = 0.017

So final answer is :

 \boxed{ \red{diff. \:  in \:  (\eta) = 0.01785}}

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