two equal and opposite chargers 4*10 power-8 columb. when placed 2*10 power-2 away from dipole.if this dipole is placed in external field 4*10 power 8 newton/columb.find value of maximum torque and work done rotating through 180 degree
Answers
Answered by
0
Answer:
q=4×10 −8
l=2×10 −2cm
E=4×10 8
Dipole moment =ql=4×10 −8 ×2×10 −4
=8×10 −12
max toeque =PEsinθ=8×10 −12 ×4×10 8
=32×10 −4
work done =PE(cosθ 1−cosθ 2 )=32×10 −4 (1−(−1))=64×10 −4
Answered by
9
SOLUTION -:
Toque acting on dipole
π = PE sin Ø or π = q x 2 l E sin Ø
Given -:
q = 4 x 10 -⁸ C , 2L = 2 x 10 -² × 10-² m
E = 4 × 10⁴ N/ C & for maximum torque ø = 90⁰
because,,
torque π = 4 x 10-⁸ x 2 x 10-⁴ x 4 x 10⁴
sin 90⁰
π = 32 x 10-⁴ N - m
work done rotating from Angle ∅
W = PE ( 1 - cos Ø ) or W = q x 2l E (1- cos Ø )
Work for 180° rotation
W = 4 x 10-⁸ x 2 x 10-⁴ x 4 x 10-⁴
( 1- cos 180° )
=> 64 x 10 -⁴ J
Similar questions