Question

Two equal and opposite charges +3nc are placed at the corners A and B of a equilateral triangle of side 1m . Calculate magnitude and direction of resultant electric field at corner "C"

Answer 1

Answer:

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Explanation:

For equilateral triangle AOB, AO=OB=BA=a  and AC=OC=BC=r

The potential at centroid C is V=kAC2q+kOC−q+kBC−q=kr2q−krq−krq=0

The net electric field  at centroid C is E=kr22q−kr2qcos30−kr2qcos30=k(0.2)r22q=0

As the total charge is zero so for dipole moment the choice of origin is independent. We assume O as origin.

dipole moment , p=−q(0)−q(Li^)+2q(2Li^+23Lj^)

or p=