Physics, asked by avnkumar251, 4 months ago

Two equal and opposite forces of 50N are acting at the opposite ends of a rod of length 1m . What is the net force and net torque?

Answers

Answered by prabakarvrl
0

Answer:

Consider the point at which resultant of the forces will act, is 'x' m from the point A.

Thus the point is (1.5 - x) m far from the point B.

Thus, using the formula Torque = Distance x Force acting

20x=30(1.5−x)

or,2x=4.5−3x

or,5x=4.5

or, x=0.9mor90cm

Thus the resultant point will be 0.9 m or 90 cm far from point A

Mark it Braillent

Answered by kingstarhere
1

Explanation:

Net force = 50 N per 1m

so, as it is acting opposite the net force become 40 Newton

as, because 1m is taken as 100cm

so, hence we got net force

 \green{ \bigstar}we \: know

torque force = net force × acting force

so, tf = 50 × 100 newton

tf = 5000 n

hope it HELPS you

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