Question

Two equal and unlike parallel forces of magnitude 17N act on a rigid body, such that moment of couple is 4.25Nm .Calculate the arm of couple

Answer 1

Answer:

arm of couple =  0.25 m or 25 cm

Explanation:

Torque or Moment of Couple = Force * arm of couple

therfore,  arm of couple = Torque or Moment of Couple/Force

arm of couple = 4.25/17 = 0.25 m or 25 cm

Answer 2

The arm of couple is 25 cm.

Explanation:

Given that,

Magnitude of two equal and unlike parallel forces is, F = 17 N

The moment of couple or the torque acting, $\tau=4.25\ N-m$

We need to find the arm of couple. When two equal and unlike forces are acting it starts to rotate. The value of torque acting on it is given by :

$\tau=F\times r$

$r=\dfrac{\tau}{F}$

$r=\dfrac{4.25}{17}$

r = 0.25 m

or

r = 25 cm

So, the arm of couple is 25 cm. Hence, this is the required solution.

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