Two equal charges are kept at a distance 10cm apart in the air when they exert a force 49 dyne on each other. Find the magnitude of each charge.
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Explanation:
F=49 dyne
F=49×10^-5N
R=10×10^-2m
F=k.q1.q2/R^2
49×10^-5=9×10^9×q^2/10^-4
q^2=(49×10^-5)×(10^-4)/(9×10^9)
q=2.33×10^-6c aprox
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