Question

Two equal charges are placed at a distance of 3 m. Calculate and mention what type of
force experiencing between the charges of 40 C.

Answer 1

Answer:

Given r=3 metre

F=1.6N q

1

=q

2

=q

∴1.6=

4πϵ

1

.

3

2

q×q

⇒1.6=9×10

9

×

9

q

2

⇒q

2

=

10

9

1.6

=

10

10

16

⇒q=

10

5

4

C

∴q=4×10

−5

C⇒q=40μC