Physics, asked by gayathrisrpk2k3, 10 months ago

Two equal charges of +2 x 10 -16 C are kept 20cm apart in air. At a point midway between them find (i) electric field intensity and ( ii ) force acting on a charge of +2 x 10 -16 C. plss answer it correctly

Answers

Answered by angelvaz21rodrigues
0

Answer:

E= 18 *10

electric field \:  =  \frac{kq}{? {r}^{?2} }  \\ r = midpoint \: 10cm \\ f = qe \: i.e. \: kqq \div   {r}^{2}

Explanation:

answer E = 18*10^5

F= 36*10^-11

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