Question

Two equal charges placed in air and separated by distance 2m repel each other with the force of 10-4gf. Calculate the magnitude of either of the charge

Answer 1

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Answer 2

The magnitude of either of the charge is $2.08\times 10^{-8}\ C$.

Explanation:

Given that,

The distance between two equal charges, r = 2 m

Force due to equal charges, $F=10^{-4}\ gf$

Since, 1 gram force (gf) = 0.0098 newtons (N)

$F=9.8\times 10^{-7}\ N$

The force between two charges is given by :

$F=k\dfrac{q^2}{r^2}$

$q=\sqrt{\dfrac{Fr^2}{k}}$

$q=\sqrt{\dfrac{9.8\times 10^{-7}\times (2)^2}{9\times 10^9}}$

$q=2.08\times 10^{-8}\ C$

So, the magnitude of either of the charge is $2.08\times 10^{-8}\ C$. Hence, this is the required solution.

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