Question

Two equal charges situated in vaccum repel each other with a force of 2.5 N .if distance between them is 12cm find the magnitude of each charge.

Answer 1

Answer:

18.97 C

Explanation:

Given:-

• $q_{1} = q_{2}=Q$    

• F = 2.5 N
• r = 12 cm

To find:-

Magnitude of each charge.

Solution:-

Using Coulomb's law;

                                      $\boxed{F=k\dfrac{q_1 q_2}{r^2}}$

Where,

F = force

k = proportionality constant

$q_1, q_2$  = charges

r = distance between charges

⇒ $F=\frac{Q^2}{r^2}$  

⇒ $Q =\sqrt{F\times r^2}$

= $\sqrt{2.5\times12\times 12}$

= $\sqrt{360}$

= 18.97 C