Question

TWO EQUAL CHORDS AB AND CD OF A CIRCLE INTERSECT EACH OTHER AT X SHOW THAT AX=CX

Answer 1

We know that AX*XB = CX*XD, o and r

8(14–8) = CX(CX+8), or

48 = CX^2 + 8CX, or

CX^2 +8CX-48+0, or

(CX+12)(CX-4) = 0

Hence CX = 4 and XD = CX+8 = 4+8 = 12.

Therefore CD = 16

Step-by-step explanation:

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