Question

Two equal circle intersect in P and Q .A is a straight line through P meet the circle in A and B .prove that QA= QB

Answer 1

Step-by-step explanation:

GIVEN :-

angle Q is perpendicular to p

so ; two angles each of 90° will be formed

proof:-

angle QPA = angle QPB (GIVEN)

QP = QP (common side )

angle QBP = angle QAP (BASE ANGLES OF RIGHT ANGLE TRIANGLE ARE EQUAL )

∆QPA = ∆QPB

using cpct rule ;

QA = QB

HENCE PROVED ;

Hope This Helps You !