Two equal circles are drawn in a rectangular shape of sides 40 cm and 20 cm. Find the are of the rest of the rectangle
Answers
Answer:
374.5 cm^2
Step-by-step explanation:
Area of shaded portion=area of circle-area of ABCD
=π×(
2
AC
)
2
−AB×BC
AC=
AB
2
+BC
2
=
28
2
+21
2
=35㎝
∴Area of shaded portion=(
7
22
×
2
35
×
2
35
)−(28×21)
=962.5−588
=374.5㎠
Step-by-step explanation:
Given length of the rectangle= 40 cm
And breadth= 20cm
Area of rectangle = l×b= 40×20= 800 sq.cm
The diameter of the circles= 20cm
Radius= d/2= 20/2= 10cm
Area of 1 circle= πr^(2)
Area of 2 circles = 2(πr^(2))
= 2(3.14×10×10)
= 2(314)= 628sq.cm
Remaining or rest of the area =Area of rectangle- Area of circles
= 800- 628
= 172 sq.cm
Hope this will help you