Question

Two equal cubes are placed adjointly in a row.Find the ratio of total surface area of the new cuboid to that of the sum of the surface areas of two cubes.​

Answer 1

Step-by-step explanation:

Let one side of the cube be 'a'

then, TSA of the cube is $6a^2$

If two cubes are joined, then resultant TSA is

=> 2($6a^2$) - $4a^2$

=> $8a^2$         ---(1)

Now, sum of surface areas of two cubes

= $12a^2$   ---(2)

So, required ratio is 4:3

Hope this helps you :)