two equal drops are falling through air with a steady velocity of 5 cm if drops coalesce the new terminal velocity will be
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when the two equal drops coalesces, volume of water remains same and a bigger drop is formed. Lets say r is radius of drop before these combine and R is radius after these combine. we have
2×
3
4
πr
3
=
3
4
πR
3
⇒R=2
1/3
r
and we know that terminal velocity V
T
∝ radius
2
, so we have
V
T
V
T
′
=
r
2
R
2
⇒V
T
′
=(
r
R
)
2
V
T
=(2
1/3
)
2
×5cms
−1
=5×4
3
1
cms
−1
Explanation:
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