Question

Two equal drops of water with radius T are falling through air with terminal velocities 'v coalesce to form a single drop. Compute the energy released in terms of r and surface tension T and the new terminal velocity. ​

Answer 1

Step-by-step explanation:

When the two equal drops coalesces, volume of water remains same and a bigger drop is formed. Lets say r is radius of drop before these combine and R is radius after these combine. 

We have

2×34πr3=34πR3⇒R=21/3r

and we know that terminal velocity VT∝ radius2, so we have

VTVT′=r2R2

⇒VT′=(rR)2VT 

=(21/3)2v

=22/3v m/s