Two equal forces act at a point. The square of their resultant is 3 times their product. Find the angle between them.
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cosine law: F2=F2+R2−2FRcos(θ2)F2=F2+R2−2FRcos(θ2)
but R2=3F2R2=3F2
F2=F2+3F2−2F3–√Fcos(θ2)F2=F2+3F2−2F3Fcos(θ2)
cancel F2F2
23–√cos(θ2)=323cos(θ2)=3
θ=60
but R2=3F2R2=3F2
F2=F2+3F2−2F3–√Fcos(θ2)F2=F2+3F2−2F3Fcos(θ2)
cancel F2F2
23–√cos(θ2)=323cos(θ2)=3
θ=60
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