Question

two equal forces act at point.the square of their resultant is three times product then the angle between those vector is

Answer 1

hlo frd here is your ans first of all here the quantity is vector so we add them by triangle law of addition .
and two force have equal magnitude so let| F1|
= x
F2 = x
and R=3(x×x)= 3x^2
by vector law of addition R^2=a^2+b^2+2abcos theta
R^2=a^3+b^2+2ab cos theta
Put the all aljebric value
3 (x^2)=x^2+x^2+2x^cos theta
(3x^2)=2 x^2 + 2x^2costheta
3x^2= x^2+ 2x^2cos theta
3x^2=x^2+2x^2cos theta
x^2/2x^2=cos theta
1/2=costheta
theta = cos 60°
hence angle is equal to 60°

Answer 2

What is ur question.....???????

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