Question

two equal forces are acting at a point with an angle of 60° between them if the resultant force is equal to 20×√3 N then find the magnitude of each focre?

Answer 1

hey

gd mrng

here is your answer

if two equal forces acting at a point with an angle Ф then magnitude of resultant force is  

= 2Fcos(Ф/2)

20√3 = 2Fcos(60/2)

10√3 = F√3/2

F = 20 N

hence magnitude of each force = 20 N

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Answer 2

let equal forces are x n
root under x²+x²+2x²cos 60=20× root 3
(on squaring both side)
then, 2x²+2x²×1/2=400×3
3x²=1200
x²=400
x=20
hence each force is of 20n