two equal forces are acting at a point with an angle of 60° between them if the resultant force is equal to 20×√3 N then find the magnitude of each focre?
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7
hey
gd mrng
here is your answer
if two equal forces acting at a point with an angle Ф then magnitude of resultant force is
= 2Fcos(Ф/2)
20√3 = 2Fcos(60/2)
10√3 = F√3/2
F = 20 N
hence magnitude of each force = 20 N
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Answered by
3
let equal forces are x n
root under x²+x²+2x²cos 60=20× root 3
(on squaring both side)
then, 2x²+2x²×1/2=400×3
3x²=1200
x²=400
x=20
hence each force is of 20n
root under x²+x²+2x²cos 60=20× root 3
(on squaring both side)
then, 2x²+2x²×1/2=400×3
3x²=1200
x²=400
x=20
hence each force is of 20n
shubhamkumar81:
thank you so much
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